If a coin is tossed five times the probability that at least one head appears on the top is

Probability of an event, P(E)=(No. of favourable outcomes)/(No. of total outcomes)

Now, 

Total no. of outcomes  of an event with two possible results = 2^n (2 raise to power n)

                                   where n is no. of times the event occurs

Here, as the coin is tossed 5 times 

Therefore, the no. of total outcomes = 2^5 = 2*2*2*2*2 = 32

As,Total cases are 32 and we need the cases with atleast one head

So, the only case possible with no head is the case where all the coins have Tails. 

Thus, favourable outcomes are 32-1 = 31

    where 1 was the event with 5 tails.

Hence, P(E)=31/32   Ans.