If $$\frac{8^5.(27)^4.6^3}{(64)^2.9^5.18^3} = 2^\alpha.2^\beta$$ then the quadratic equation for which $$\alpha$$ and $$\beta$$ are the roots is

A

$$x^2 + 2x + 3 = 0$$

B

$$x^2 - 2x - 3 = 0$$

C

$$x^2 + 2x - 3 = 0$$

D

$$x^2 - 2x + 3 = 0$$