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A die is thrown twice. What is the probability of getting a sum 7 from both the throws?
$$\frac{5}{18}$$
$$\frac{1}{18}$$
$$\frac{1}{9}$$
$$\frac{1}{6}$$
$$\frac{5}{36}$$
The number 7 can be obtained in 6 ways. (6,1), (1,6), (5,2), (2,5), (4,3), (3,4).
Required probability = 6/36 = 1/6
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