AP ICET 2nd May 2018 Shift-1

Question 144

The standard deviation of five consecutive positive integers is

Solution

five consecutive positive integers = 1,2,3,4,5

Mean = 3

Standard deviation = $$\sqrt{\frac{\left(\ \left(3-1\right)^2+\left(3-2\right)^2+\left(3-3\right)^2+\left(3-4\right)^2+\left(3-5\right)^2\right)}{5}}$$ = $$\sqrt{\ 2}$$


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