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If $$\sigma$$ is the standard deviation of $$x_i(i = 1, 2, ... ... ..., n)$$ then the variation of $$5x_i + 3(i = 1, 2, 3, ... ... ..., n)$$ is
$$\sqrt{5}$$
$$5 \sigma$$
$$5 \sigma^2 + 9$$
$$25 \sigma^2$$
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