Two circles are of radii 7 cm and 2 cm their centres being 13cm apart. Then the length of direct common tangent to the circles between the points of contact is
Let the length of direct common tangent be 'n' cm.
In $$\triangle$$ AOB,
AO=7-2=5 cm, AB=13 cm, BO=n
Using pythagoras's theorem in $$\triangle$$ AOB,
$$AO^{2}+BO^{2}=AB^{2}$$
$$5^{2}+n^{2}=13^{2}$$
$$n=12 cm$$
Hence Option A is correct.
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