In the following questions two equations numbered I and II are given. You have to solve both the equations and
Give answer a: if x > y
Give answer b: if x ≥ y
Give answer c: if x < y
Give answer d: if x ≤ y
Give answer e: if x = y or the relationship cannot be established.
I. $$x^{2}-3x-88=0$$
II. $$y^{2}+8y-48=0$$
I.$$x^{2} - 3x - 88 = 0$$
=> $$x^2 + 8x - 11x - 88 = 0$$
=> $$x (x + 8) - 11 (x + 8) = 0$$
=> $$(x + 8) (x - 11) = 0$$
=> $$x = -8 , 11$$
II.$$y^{2} + 8y - 48 = 0$$
=> $$y^2 + 12y - 4y - 48 = 0$$
=> $$y (y + 12) - 4 (y + 12) = 0$$
=> $$(y + 12) (y - 4) = 0$$
=> $$y = -12 , 4$$
$$\therefore$$ No relation can be established.
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