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On a particular day, sweets were to be equally distributed among 960 students of a school. However, on that particular day 360 students remained absent. Hence each student present on that day got three sweets extra. Had all 960 students remained present that day, how many sweets would each student have got ?
Let each student get $$x$$ sweets
=> $$960 \times x = (960 - 360) \times (x + 3)$$
=> $$960 x = 600 x + 1800$$
=> $$360 x = 1800$$
=> $$x = \frac{1800}{360} = 5$$
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