The susceptibility of a paramagnetic material is $$99$$. The permeability of the material in Wb/A - m, is
[Permeability of free space $$\mu_0 = 4\pi \times 10^{-7}$$ Wb/A - m]

Given: Susceptibility $$\chi = 99$$, and $$\mu_0 = 4\pi \times 10^{-7}$$ Wb/A-m.

The relationship between permeability and susceptibility is:

$$\mu = \mu_0(1 + \chi)$$

Substituting the values:

$$\mu = 4\pi \times 10^{-7} \times (1 + 99)$$

$$\mu = 4\pi \times 10^{-7} \times 100$$

$$\mu = 4\pi \times 10^{-5} \text{ Wb/A-m}$$

The correct answer is Option A.

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The susceptibility of a paramagnetic material is $$99$$. The permeability of the material in Wb/A - m, is[Permeability of free space $$\mu_0 = 4\pi \times 10^{-7}$$ Wb/A - m]