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At a certain place the angle of dip is 30° and the horizontal component of earth's magnetic field is 0.5 G. The earth's total magnetic field (in G), at that certain place, is
The angle of dip is $$\delta = 30°$$ and the horizontal component of Earth’s magnetic field is $$B_H = 0.5$$ G. These quantities are linked by the relation $$B_H = B\cos\delta$$, where $$B$$ denotes the total magnetic field. Solving for $$B$$ gives
$$ B = \frac{B_H}{\cos\delta} = \frac{0.5}{\cos 30°} = \frac{0.5}{\frac{\sqrt{3}}{2}} = \frac{1}{\sqrt{3}} \text{ G} $$Therefore, the correct answer is Option A: $$\frac{1}{\sqrt{3}}$$.
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