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A paramagnetic sample shows a net magnetisation of 6 A/m when it is placed in an external magnetic field of 0.4 T at a temperature of 4 K. When the sample is placed in an external magnetic field of 0.3 T at a temperature of 24 K, then the magnetisation will be:
$$I \propto \frac{B}{T} \implies \frac{I_2}{I_1} = \left(\frac{B_2}{B_1}\right) \left(\frac{T_1}{T_2}\right)$$
$$\frac{I_2}{6} = \left(\frac{0.3}{0.4}\right) \left(\frac{4}{24}\right) = \left(\frac{3}{4}\right) \left(\frac{1}{6}\right) = \frac{1}{8}$$
$$I_2 = \frac{6}{8} = 0.75\text{ A/m}$$
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