$$a$$, $$b$$, $$c$$, $$d$$, $$e$$ are five consecutive natural numbers. Another natural number $$n$$ always divides $$(a \times b \times c \times d \times e)$$ completely. Then the greatest possible value of $$n$$ is ______.

Among any five consecutive natural numbers there is a multiple of 5, at least one multiple of 3, and enough even numbers to supply a factor of 8, so the product is always divisible by $$5! = 120$$. The product $$1 \times 2 \times 3 \times 4 \times 5 = 120$$ shows that no larger number can always divide it. Hence the greatest such $$n$$ is 120.