The solubility of AgCl(s) with solubility product $$1.6 \times 10^{-10}$$ in $$0.1 M Nacl$$ solution would be

A

$$1.6 \times 10^{-9} M$$

B

$$1.6 \times 10^{-11} M$$

C

zero

D

$$1.26 \times 10^{-5} M$$