A = \begin{bmatrix}2 & 3 \\\4 & 5 \end{bmatrix} \Rightarrow \mid A^5 \mid =

Question 132

$$A = \begin{bmatrix}2 & 3 \\4 & 5 \end{bmatrix} \Rightarrow \mid A^5 \mid =$$

Solution

Upon successive multiplication, obtain the matrix $$A^5$$
Its terms are:
$$A_{11}=6140$$, $$A_{12}=8097$$, $$A_{21}=10796$$, $$A_{22}=14237$$

Cross multiplication and subtraction of terms results in determinant = -32

Create a FREE account and get:

Download Maths Shortcuts PDF
Get 300+ previous papers with solutions PDF
500+ Online Tests for Free

AP ICET 2nd May 2018 Shift-2

$$A = \begin{bmatrix}2 & 3 \\4 & 5 \end{bmatrix} \Rightarrow \mid A^5 \mid =$$

Login to your Cracku account

Hello! 👋

Ready to Unlock Your Success?

Please Enter Your OTP

Please enter the following details

Create a free Cracku account