Question 131

Sujata scored 2240 marks in an examination that is 128 marks more than the minimum passing percentage of 64%. What is the percentage of marks obtained by Meena if she scores 907 marks less than Sujata?

Solution

Let maximum marks in the examination = $$100x$$

Minimum passing marks = $$\frac{64}{100} \times 100x = 64x$$

Marks scored by Sujata = $$2240$$

Acc to ques,

=> $$64x + 128 = 2240$$

=> $$64x = 2240 - 128 = 2112$$

=> $$x = \frac{2112}{64} = 33$$

=> Maximum marks = $$100 \times 33 = 3300$$

Marks scored by Meena = $$2240 - 907 = 1333$$

$$\therefore$$ % marks obtained by Meena = $$\frac{1333}{3300} \times 100$$

= $$40.39 \% \approx 40 \%$$

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