Question 130

A metallic sphere of radius 6 cm is melted down and re casted into three metallic spheres of equal radii. Find the radius of the spheres formed.

Solution

Volume of the initial sphere = $$\frac{4}{3}*\pi *r^3$$ = $$\frac{4}{3}*\pi *6^3$$
Volume of each of the smaller spheres = $$\frac{4}{3}*\pi *r^3$$
==> 3*$$\frac{4}{3}*\pi *r^3$$ = $$\frac{4}{3}*\pi *6^3$$ ==> $$r^3 = 6^3/3$$ ==> $$r^3 = 72$$ ==> $$r = 2*\sqrt[3]{9}$$
So the correct option to choose is E.

Video Solution

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