A ladder leaning against a wall makes an angle of 60° with the horizontal. If the foot of the ladder is 10 m away from the wall. what is the length of the ladder?
Given,
$$\angle\ ACB=\ 60^{\circ\ }$$
BC= 10 cm
We know that, $$\cos\ \theta\ =\frac{Base}{Hypotenuse}$$
$$\cos\ \theta\ =\frac{BC}{AC}$$
$$\cos\ 60^{\circ\ }=\ \frac{10}{AC}$$
$$\frac{1}{2}\ =\ \frac{10}{AC}$$
$$AC=20m$$
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