Sign in
Please select an account to continue using cracku.in
↓ →
JEE WhatsApp Group
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Peter starts from a point A in a playground and walks $$100\ \text{m}$$ towards East. Then he walks 30 m towards North and then 70 m towards West and then finally 10 m North to reach the point B. The distance between A and B (in metres) is
Walking 100 m East and later 70 m West leaves him $$100 - 70 = 30$$ m East of A. Walking 30 m North and later 10 m North leaves him $$30 + 10 = 40$$ m North of A. So AB is the longest side of a right angled triangle with the other two sides 30 m and 40 m, giving $$AB = \sqrt{30^2 + 40^2} = \sqrt{2500} = 50$$ m.
_1.webp)
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
91- 6303239042
