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One end of a diameter of a circle having centre at $$(-2, 5)$$ is $$(2, 3)$$. The other end of the diameter is
The centre is the mid point of the diameter. If the other end is $$(h, k)$$, then $$\frac{2 + h}{2} = -2$$ and $$\frac{3 + k}{2} = 5$$, giving $$h = -6$$ and $$k = 7$$. So the other end is $$(-6, 7)$$.
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