Join WhatsApp Icon JEE WhatsApp Group
Question 13

Determine the electric dipole moment of the system of three charges, placed on the vertices of an equilateral triangle, as shown in the figure:

Each individual dipole vector has a magnitude of: $$p_1 = p_2 = ql$$

The two dipole vectors point from the top vertex downward toward the bottom-left and bottom-right vertices. Because the triangle is equilateral, the angle between these two vectors is $$60^\circ$$.

By symmetry, the horizontal components of these vectors cancel each other out, while their vertical components add together along the negative y-direction ($$-\hat{j}$$).

The net dipole moment ($$\vec{p}_{\text{net}}$$) is calculated by adding the vertical components:

$$\vec{p}_{\text{net}} = -\left(p_1 \cos 30^\circ + p_2 \cos 30^\circ\right)\hat{j}$$

$$\vec{p}_{\text{net}} = -\left(ql \frac{\sqrt{3}}{2} + ql \frac{\sqrt{3}}{2}\right)\hat{j} = -\sqrt{3}ql\hat{j}$$

Get AI Help

Create a FREE account and get:

  • Free JEE Mains Previous Papers PDF
  • Take JEE Mains paper tests
Ask AI