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Answer the following questions based on the information given below.A bowl contains 4 red, 3 green, 2 blue and 5 black marbles.
If two marbles are drawn random, what is the probability that they are green ?
$$\frac{4}{91}$$
$$\frac{51}{91}$$
$$\frac{4}{13}$$
$$\frac{1}{13}$$
None of these
Probability of drawing 2 green = $$^3C_2 / ^{14}C_2$$ = 3 / (7*13) = 3 / 91
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