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Question 123
A number when successively divided by 5 and 6 gives remainders 3 and 2 respectively. What will be the remainders if the number is successively divided by 3 and 4 ?
Solution
Going in the reverse orderÂ
When a number is divided by 6, the remainder is 2 => the number is of the form 6k+2
When 6k+2 is divided by 5,the remainder is 3 => the number is of the form 5(6k+2)+3 = 30k+13
When 30k+13 is divided by 3, the remainder is 1.
The remaining is 3(10k+4), so when 10k+4 is divided by 4, the remainder is 0 or 2
Among the given options 1, 2 satisfies this condition.
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