Rutuja bought two articles-article A at X and article B at X + 50. She sold article A at 20% profit and article B at 10% loss, and earned 35/- as profit on the whole deal.
Quantity :
I. Profit earned by Rutuja on selling article A (in ).
II. Loss incurred (in ) when an article which costs 480/- is sold at 20% loss.

Cost price of article A = $$x$$ and cost price of article B = $$x + 50$$

Selling price of article A = $$\frac{120}{100} \times x = \frac{6x}{5}$$

Selling price of article B = $$\frac{90}{100} \times (x + 50)$$

Selling price of both articles after Rs. 35 profit = $$(x + x + 50 + 35) = 2x + 85$$

=> $$(\frac{6x}{5}) + (\frac{90}{100} \times (x + 50)) = 2x + 85$$

=> $$\frac{6x}{5} + \frac{9x}{10} + 45 = 2x + 85$$

=> $$\frac{21x}{10} - 2x = 85 - 45$$

=> $$\frac{x}{10} = 40$$

=> $$x = 40 \times 10 = 400$$

Quantity I : Profit = $$\frac{20}{100} \times 400 = Rs. 80$$

Quantity II : Loss = $$\frac{20}{100} \times 480 = Rs. 96$$

$$\therefore$$ Quantity I < Quantity II