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The sum of the first 10 terms of the progression 2, 5, 8, 11, .... is
155
29
165
310
Solution
Sum of A.P. = $$\frac{n}{2}$$ (2a + (n-1)d)
Here, a = 2
d = 8 - 5 = 5 - 2 = 3
and A/q n = 10.
Putting the values in the Formula
S = $$\frac{10}{2}$$ (2 x 2 + (10-1)3)
=5 (4 + 27)
= 5 x 31
= 165 Answer
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