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Question 119
For which of the following values of x the inequality $$3(x^{2} - 4x + 4) < x $$ gets satisfied ?
Solution
Given inequality, $$3(x^{2} - 4x + 4) < x$$
=> $$3x^{2} - 13x + 12 < 0$$
=> On solving the equations we get x = 3, 4/3
On the checking for the value of the equation in 3 regions, we see that it is negative only for $$ \frac{4}{3} < x < 3$$
so option c is correct
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