Question 118

$$\sin^2 60^\circ + \cos^2 225^\circ + \tan^2 210^\circ + \cot^2 240^\circ =$$

Solution

Sin 60 = (root 3)/2
Cos 225 = cos (180 + 45) = - cos 45 = -1/(root 2)
Tan 210 = tan (180 + 30) = tan 30 = 1/(root 3)
Cot 240 = cot (180 + 60) = cot 60 = 1/(root 3)

Squaring up all terms and adding, we get answer as 23/12

Share on Whatsapp Share on Whatsapp

Create a FREE account and get:

Download Maths Shortcuts PDF
Get 300+ previous papers with solutions PDF
500+ Online Tests for Free

AP ICET 2018 Question Paper Shift-2 (2nd May)

$$\sin^2 60^\circ + \cos^2 225^\circ + \tan^2 210^\circ + \cot^2 240^\circ =$$

Login to your Cracku account

Hello! 👋

Ready to Unlock Your Success?

Please Enter Your OTP

Please enter the following details

Create a free Cracku account

Get Started with 5000+ Free CAT Questions & Mock Tests with Detailed Solutions!