Question 117
Equation of perpendicular bisector of the line segment joining (13, —2) and (-5, 10) is
Solution
The general line through two points (a,b)(a,b) and (c,d)(c,d) is
(c − a) (y−b) = (d −b) (x − a)
In our case, that is
(-5 - 13)(y + 3) = 12 (x − 13) = -18(y +2 ) = 12 (x−13)
which we can write
12x + 18y = -120
2x + 18y = -20 Answer
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