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A bag contains 5 red, 4 green and 3 black balls. Three balls are drawn out from it at random. Find the probability of drawing exactly 2 red balls
Number of ways in which we can select 2 red balls and 1 ball out of remaining 7 balls = 5C2 * 7.
Total number of ways of selecting 3 balls = 12C3.
Required Probability = $$\frac{5C2\times\ 7}{12C3}=\frac{7}{22}$$
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