The IUPAC name of the compound

• Step 1: Identify the Principal Functional Group

  The compound contains a six-membered carbon ring with a hydroxyl group ($$-\text{OH}$$) and two methyl groups ($$-\text{CH}_3$$). According to IUPAC priority rules, the principal functional group is the alcohol ($$-\text{OH}$$), which gives the molecule the suffix -ol.




• Step 2: Number the Parent Ring

  The ring is numbered to give the principal functional group the lowest possible locant:

  • The carbon atom bonded to the morning high-priority group ($$-\text{OH}$$) is assigned C1.
  • We then number around the ring towards the substituents to give them the lowest possible numbers. Numbering clockwise leads to the methyl groups residing on C3.

  This establishes a numbering sequence of 1, 3, 3 for all attached functional groups.




• Step 3: Identify and Name the Substituents

  There are two identical methyl groups located at the third carbon position, which are combined and prefixed as 3,3-dimethyl.




• Step 4: Assemble the Complete Name

  Combining the prefixed substituents, the parent cyclic alkane root (cyclohexane), and the principal suffix gives:

  $$\text{3,3-dimethyl} + \text{cyclohexan} + \text{1-ol} = \mathbf{3,3-dimethyl-1-cyclohexanol}$$

Following standard priority rules ensures that the alcohol group takes precedence over the alkyl groups at position 1.

Answer: Option C — 3,3-dimethyl-1-cyclohexanol