In finding the HCF of two numbersby division method, the quotients are 1, 8 and 2 respectively, and the last divisor is 105. What is the sum of the numbers?

Let the two numbers be $$a$$ and $$b$$

The table shows that when $$b$$ is divided by $$a$$, quotient is 1 and remainder is $$c$$, which becomes divisor in 2nd step and $$a$$ becomes dividend, now quotient is 8 and remainder is 105 and in the final step, 105 becomes divisor with $$c$$ being the dividend, 2 is quotient and remainder is 0.

Thus, $$c=105\times2+0=210$$

$$b=8c+105=8\times210+105=1785$$

$$a=1\times b+c=1785+210=1995$$

Thus, sum of numbers = $$a+b=1995+1785=3780$$

=> Ans - (C)