110! mod 107^2 ??

We have
110! mod 107^2
110*109*108*107 *106! mod 107^2
Taking 1 107 as common
we get
110*109*108*106! mod 107
Now as 107 is prime so 106! mod 107 =-1 (wilson theorem)
we get 3*2*1*-1 ( as remainders)
= -6
=101
Now since 107 was taken common above
so we will multiply here
therefore remainder becomes : 101*107 =10807

Thankyou so much sir..