110! mod 107^2 ??

We have 110! mod 107^2 110*109*108*107 *106! mod 107^2 Taking 1 107 as common we get 110*109*108*106! mod 107 Now as 107 is prime so 106! mod 107 =-1 (wilson theorem) we get 3*2*1*-1 ( as remainders) = -6 =101 Now since 107 was taken common above so we will multiply here therefore remainder becomes : 101*107 =10807

Thankyou so much sir..