Question 11
The positive real numbers $$a, b, c$$ satisfy: $$\frac{a}{2b+1}+\frac{2b}{3c+1}+\frac{3c}{a+1}=1$$ and $$\frac{1}{a+1}+\frac{1}{2b+1}+\frac{1}{3c+1}=2$$. What is the value of $$\frac{1}{a}+\frac{1}{b}+\frac{1}{c}$$?
Correct Answer: 12
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