Solution
Given : $$x-\frac{1}{x}=2$$
Cubing both sides, we get :
=> $$(x-\frac{1}{x})^3=(2)^3$$
=> $$x^3-\frac{1}{x^3}-3(x)(\frac{1}{x})=8$$
=> $$x^3-\frac{1}{x^3}-3=8$$
=> $$x^3-\frac{1}{x^3}=8+3=11$$
=> Ans - (C)
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