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If $$x-\frac{1}{x}=2$$, then the value of following is: $$x^3-\frac{1}{x^3} =?$$
Given : $$x-\frac{1}{x}=2$$
Cubing both sides, we get :
=> $$(x-\frac{1}{x})^3=(2)^3$$
=> $$x^3-\frac{1}{x^3}-3((x)-(\frac{1}{x}))=8$$
=> $$x^3-\frac{1}{x^3}-3*2=8$$
=> $$x^3-\frac{1}{x^3}=8+6=14$$
=> Ans - (C)
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