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Question 106
Let "s" be the surface area of a cube of edge 9 em. This cube is cut into smaller cubes of edge 3 cm each, If "S" is the sum of the surface areas of all the smaller cubes, then s : S =
Solution
Number of smaller cubes obtained = (Volume of original cube)/(Volume of each of the smaller cube)
Hence, Number of smaller cubes obtained = (9*9*9)/(3*3*3) = 27
Now, surface area "s" of the original cube = 6*(9*9) sq. cm
Sum of Surface areas of all the smaller cubes, S = 27 * [6*(3*3)]
Hence, s:S = 1:3
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