Question 103

The sum of the digits of a two-digit number is 8 and the digit in the ten’s place is three times the digit in the unit’s place What is the number ?

Solution

Let x be the tens digit and y be the units digit of the two-digit number.

Given, x + y = 8 - (1)

and x = 3y -(2)

Substituting (2) in (1) we get 4y = 8

i.e y = 2

Putting the value of y in (1) we get x = 6. Thus the number is 62

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