Question 103
The sum of the digits of a two-digit number is 8 and the digit in the ten’s place is three times the digit in the unit’s place What is the number ?
Solution
Let x be the tens digit and y be the units digit of the two-digit number.
Given, x + y = 8 - (1)
and x = 3y -(2)
Substituting (2) in (1) we get 4y = 8
i.e y = 2
Putting the value of y in (1) we get x = 6. Thus the number is 62
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