Excess of KI reacts with $$CuSO_4$$ solution and then $$Na_2S_2O_3$$ solution is added to it. Which of the statements is incorrect for this reaction?

A

$$Cu_2I_2$$ is reduced

B

Evolved $$I_2$$ is reduced

C

$$Na_2S_2O_3$$ is oxidized

D

$$CuI_2$$ is formed