A 280 metres long train, travelling at a uniform speed, crosses a platform in 60 seconds and a man standing on the platform in 20 seconds. What is the length of the platform ?
Let length of platform = $$l$$ metres
Let speed of train = $$x$$ m/s
Using, $$time = \frac{distance}{speed}$$
=> $$\frac{280}{x} = 20$$
=> $$x = \frac{280}{20} = 14$$ m/s
Time taken while crossing the platform,
=> $$\frac{280 + l}{14} = 60$$
=> $$280 + l = 60 \times 14 = 840$$
=> $$l = 840 - 280 = 560$$ metres
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