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In the given figure, $$AB$$, $$HG$$, $$CD$$ and $$FE$$ are parallel. Also, $$AB=6$$, $$GH=4$$, $$CD=5$$, $$FE=9$$ and $$BC=8$$. The distances between each indicated pair of parallel lines are $$3$$. The area of the complete figure is
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Divide the figure into two trapezia and the central rectangle shown in the diagram. Their areas are $$\frac{1}{2}(3+4)\times3$$, $$3 \times 11$$ and $$\frac{1}{2}(5+6)\times3$$. The total is $$\frac{21}{2}+33+\frac{33}{2}=60$$.
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