Charges $$Q_1$$ and $$Q_2$$ are at points A and B of a right-angled triangle OAB. The resultant electric field at point O is perpendicular to the hypotenuse, then $$Q_1/Q_2$$ is proportional to:

A

$$\frac{x_1^3}{x_2^3}$$

B

$$\frac{x_2}{x_1}$$

C

$$\frac{x_1}{x_2}$$

D

$$\frac{x_2^2}{x_1^2}$$