A soap bubble, blown by a mechanical pump at the mouth of a tube increases in volume with time at a constant rate. The graph that correctly depicts the time dependence of pressure inside the bubble is given by:

Given that the volume $$V$$ increases at a constant rate with time $$t$$:

$$V = c_1 t$$

$$\frac{4}{3}\pi r^3 = c_1 t \implies r = c_2 t^{1/3}$$

The total pressure $$p$$ inside the soap bubble is:    $$p = p_0 + \frac{4T}{r}$$

Substituting the value of $$r$$:    $$p = p_0 + \frac{4T}{c_2 t^{1/3}}$$

This matches the linear straight-line equation form $$y = c + mx$$, where the independent variable on the horizontal axis is $$\frac{1}{t^{1/3}}$$.