A person lifts luggage of 20 kg from the ground and puts it on his head 2 in above the ground. Calculate the work done by him. (g = l0 $$ms^{-2}$$)
M = 20kg
g = 10m/s^2
h = 2m
As work done by an object is equal to the potential energy stored in an object.
Therefore,
W = mgh
$$= 20\times 10\times 2$$
= 400 J
Option B is correct.
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