Question 1

There is a 6-digit number in which the first and the fourth digit from the first are the same, the second and the fifth digit from the first are the same and the third and the sixth digit from the first are the same. Then the number is always

Name: There is a 6-digit number in which the first and the fourth digit from the first are the same, the second and the fifth digit from the first are the same and the third and the sixth digit from the first are the same. Then the number is always
Uploaded: 2026-08-10T17:43:38.136229+05:30
Duration: 4 min 29 s
Description: There is a 6-digit number in which the first and the fourth digit from the first are the same, the second and the fifth digit from the first are the same and the third and the sixth digit from the first are the same. Then the number is always

Solution

Let the number be $$abcabc$$. Its value is $$100000a+10000b+1000c+100a+10b+c=1001(100a+10b+c)$$. Since $$1001=7\times 11\times 13$$, the number is always divisible by $$11$$.

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