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Question 1

The value of $$\frac{9999 + 7777 + 5555}{8888 + 6666 + 4444} $$ is

Solution

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Every term in the numerator and in the denominator is a multiple of 1111. Taking 1111 common, the numerator is $$1111 \times (9 + 7 + 5) = 1111 \times 21$$ and the denominator is $$1111 \times (8 + 6 + 4) = 1111 \times 18$$. Cancelling 1111 from both gives $$\frac{21}{18} = \frac{7}{6}$$.

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