The density of silver is $$10.8 \times 10^3kgm^{-3}$$ and the density of water is $$10^3kgm^{-3}$$. What is the relative density of Ag?
The density of silver is $$10.8 \times 10^3kgm^{-3}$$ and the density of water is $$10^3kgm^{-3}$$.
In this case,
Relative density $$= \frac{Density of silver}{Density of water}$$
Relative density = $$\frac{10.8 \times 10^3kgm^{-3}}{10^3} kgm³$$
$$ = 10.8$$
Option D is correct.
Create a FREE account and get:
