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If $$x$$ and $$y$$ are two positive integers such that $$xy = 2015$$ then the number of distinct values $$x$$ can take is
$$x$$ can be any positive divisor of 2015, with $$y = \frac{2015}{x}$$. Since $$2015 = 5 \times 13 \times 31$$, the number of divisors is $$2 \times 2 \times 2 = 8$$.
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