Question 1

If 2011 is written as the sum of 11 consecutive primes in their ascending order, then the $$6^{\text{th}}$$ prime is

Solution

The average of the 11 primes is $$\frac{2011}{11} \approx 183$$, so they lie around 183. Checking, $$157 + 163 + 167 + 173 + 179 + 181 + 191 + 193 + 197 + 199 + 211 = 2011$$. The 6th (middle) prime in this list is 181.

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