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5 years, 7 months ago
- A is 1.5 times efficient than B therefore takes 8 days less than B to complete a work. If A and B work on alternate days and A works on first day, then
in how many days the work will be completed?
5 years, 7 months ago
19 days
number of days taken by A is 16 and B is 24
let total work be 48 units then the efficiency of A is 3 and B is 2
if they work on alternate days then in 2 days 5 units will be completed hence in 18 days 45 units will be completed and A will work on last days to complete last 3 units and make it 48 units.
5 years, 7 months ago
Answer is 19 days
Let number of days taken by A be X
So, number of days taken by B will be 1.5X
The difference is 8, so X = 16.
So, A completes in 16 days and B in 24 days.
If both of them work on alternate days, in two days, the work done will be 1/16+1/24 = 5/48
So, in 9*2 = 18 days, they complete 45/48 of the work.
The remaining 3/48 = 1/16 of the work will be completed by A on the 19th day.
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