While covering a distance of 24 km, a man notices that after walking for 1 hour and 40 minutes, the distance covered by him was 75 of the remaining distance. His speed of
walking is(1) 9 km/hour (2) 6 km/hour (3) 10 km/hour (4) 8 km/

Total distance = 24km
Distance covered=5/7 of Distance left
Time walked = 1hr 40 min =5/3hr
Lets take the speed as ‘x’kmph

Distance covered= speed X time

Distance=x X 5/3 hr

Distance=5x/3 km

remaining=total- covered

=(24-5x/3)

We know that

distance covered=5/7 of distance left

5x/3=5/7(24−5x/3)

5x/3=5/7 X (72−5x)/3

Further equating

7x=72−5x

12x=72

x=6 kmph

x=6 x518 m/s

x=5/3 m/s

x= 1.666….. m/s

Super tq

Hi Abhilash,

I think the question should be "...5/7th of the remaining distance..."

In this case,

Distance travelled = d
Remaining distance = 24-d
So, d = 5/7 * (24 - d)
=> 7d = 120 - 5d => 12d = 120 => d = 10 km
Time = 5/3 hours
So, speed = 10/(5/3) = 6 kmph