Two trains start simultaneously in the opposite direction from two points X and Y and arrive at their destinations 16 and 9 hours, respectively, after they meet each other. what is the speed of train from Y if the speed of train from X is 90 kmph?

please explain it in traditional method.

Let the distance be 'd' between the two stations.
meeting point distance from x : (d/(x+y))*x = 90d/(90+y)
This distance is covered by train Y in 9 hours.
9y = 90d/(90+y)

Similarly,
16*90 = yd/(90+y)

divide both equations :
(9y)/(16*90) = 90d/yd
y = 120

Suppose the distance between points X and Y be ‘d’. Now assume they meet at some point which is at a distance of ‘b’ from X. So by the time train from X reaches ‘b’ , train from Y would have covered (d-b) distance. As the time taken is same to meet at point ‘b’ initially.
First equation comes out to be- ( time taken is same):-
b/90 = (d-b)/s ( s is the speed of train from Y)

Now second equation will be formed on the basis of time they have taken to reach their respective destination after meeting each other.
For train X
(d-b) = 90*16
For train from Y
b = s*9

Keep the values of b and (d-b) in first equation u will get the speed of the other train as 120

No Isha... ans is 120

Thanks Himanshu 😊

Thanks Abhishek 😊

90?