There are two alloys of gold and silver. In the first alloy there is twice as much as gold as silver,and in second alloy there is 5 times less gold than silver.

How many times more must we take of the second alloy than the first in order to obtain a new alloy in which there would be twice as m…

Question

There are two alloys of gold and silver. In the first alloy there is twice as much as gold as  silver,and in second alloy there is 5 times less gold than silver. 

How many times more must we take of the second alloy than the first in order to obtain a new alloy in which there would be twice as much silver as gold

Ranbir Kapoor · Answer

A1: S = x , G=2xA2: S=6y, G=yTaking 'a' quantities of A1 and 'b' quantities of A2.A3: ax+6yb=2(2ax+yb)a/b= 3x/4ySince we do not know amount of Gold and Silver in A1 and A2. I don't think we'll be able to answer any better.

Kartikey Keshari · Answer

G   S
A1 -  1 : 2   =  2kg + 4kg     {let both alloy 6 kg }

A2 -. 5 : 1   =  5kg + 1 kg

We need new alloy - 1:2 
If we add  one A1 and one A2 gold and silver would be 5kg and 7 kg but 5:7 ≠ 1:2

if we add one A1 and two A2

Gold = 4 + 1+1 = 6 kg 
Silver = 2+5+5 = 12 kg

6kg : 12 kg ~ 1 : 2. So we must to take two tims more of the second alloy than the first.

Two times ,,  Ans.

SUVAM DEBNATH · Answer

2 times

Raviraj · Answer

Explain please

Atul gupta · Answer

3 times more??

nasreen fathima · Answer

Please give solution for this question

Suri Gangula · Answer

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